please someone answer this question
the correct answer will be marked as brainliest
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yashchoudhary5533005:
yes i will mark it
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Answer:
Explanation:
1. Mass portion from 107Ag = 106.905amu*0.5184
=> 51.42amu
2. Mass portion from 109Ag= 108.904amu*0.4816
=> 52.44amu
So, Atomic Mass of Ag= 51.42+52.44amu
=> 103.86amu.....
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