Question

Please someone give me ANSWER ​

Answer 1

Answer:

Let the ten's digit be a and unit's digit of number be (a + 3), and thus number formed be : [10a + (a + 3)]

• According to the Question :

⇒ Number : Sum of digits = 4 : 1

⇒ [10a + (a + 3)] / [a + (a + 3)] = 4 / 1

⇒ [11a + 3] / [2a + 3] = 4 / 1

⇒ 1 × [11a + 3] = 4 × [2a + 3]

⇒ 11a + 3 = 8a + 12

⇒ 11a - 8a = 12 - 3

⇒ 3a = 9

⇒ a = 9/3

⇒ a = 3

• Ten's digit = a = 3
• Unit's digit = (a + 3) = (3 + 3) = 6

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• Number formed will be :

⇢ Number = 10a + (a + 3)

⇢ Number = 10(3) + (3 + 3)

⇢ Number = 30 + 6

⇢ Number = 36

∴ Hence, required number is (3) 36.

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Verification –

L.H.S

⇒ Number : Sum of digits

⇒ [10a + (a + 3)] : [a + (a + 3)]

⇒ [10(3) + (3 + 3)] : [3 + (3 + 3)]

⇒ [30 + 6] : [3 + 6]

⇒ 36 : 9

• Dividing both by 9

⇒ 4 : 1

R.H.S

⇒ 4 : 1

Answer 2

Answer:

hope so it will helpful to you