Question

Two Years Ago Father Was Three Times As Old As His Son And Two Years Hence Twice His Age Will Be Equal To Five Times That Of His Son Find Their Presents Ages

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Answer 1

Answer:

Let us consider

Son's age = X

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Two years ago son's age X- 2

His Father's age at that time = 3(x - 2)

Present age of Father 3X - 6+ 2

The present age of Father = 3X - 4

Two years hence father's age = 3X - 4 + 2

Two years hence father's age 3X- 2

Two years hence son's age X + 2

Given:

5 x (X + 2) = 2 x (3x - 2)

5X + 10 = 6X -

X = 14

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Answer 2

Answer:

Let son's age = x

Two years ago son's age= x-2.

His Father's age at that time = 3(x-2).

Present age of Father = 3x-6+2=3x-4

Two years hence father's age=3x-4+2=3x-2.

Two years hence son's age = x+2.

Given :-5*(x+2)=2*(3x-2)

5x + 10= 6x - 4

10+4=6x-5x

14=x

SON'S PRESENT AGE : 14 years.

FATHER'S PTESENT AGE: 38 years.

Step-by-step explanation: