Question

please someone solve this​

Answer 1

according to me this answer is right....

seee ur solution in pictures .....

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Answer 2

Step-by-step explanation:

$\sf \: \frac{1}{ \frac{x + 1}{x} } + \frac{x + 1}{x} = \frac{25}{12} \\ \\ \\ \sf \: \frac{x + 1}{x} = t \\ \\ \\ \sf \: \frac{1}{t} + t = \frac{25}{12} \\ \\ \\ \sf \: \frac{1 + {t}^{2} }{t} = \frac{25}{12} \\ \\ \\ \sf \: 12 + {12t}^{2} - 25t \\ \\ \\ \sf \: {12t}^{2} - 25t + 12 = 0 \\ \\ \\ \sf \: {12t}^{2} - 16t - 9t + 12 = 0 \\ \\ \\ \sf \: \underbrace{ 4t (3t - 4) }- \underbrace{3(3t - 4) }= 0 \\ \\ \\ \sf \: 3t - 4 = 0 \: \: \: \: \: \: \: \: \:4t - 3 = 0 \\ \\ \\ \sf \boxed{ \sf t - \frac{4}{3} }\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \sf \: t = \frac{4}{4} } \\ \\ \\ \sf \: \frac{x + 1}{x} = \frac{4}{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \frac{x + 1}{x } = \frac{3}{4} \\ \\ \\ \sf \: 3x + 3 = 4x \: \: \: \: \: \: \: \: \: \: \: \: 4x + 4 = 3x \\ \\ \\ \sf \fbox{x = 3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \fbox{x = - 4}$