Math, asked by arminsofi2, 8 months ago

please someone solve this resolve into factors​

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Answered by Mysterioushine
2

2a {}^{2} + 5a + 2  \\  \\  = 2a {}^{2} + 4a + 1a + 2 \\  \\  = 2a(a + 2)  + 1(a + 2) \\  \\  = (2a + 1)(a + 2)

Answered by hchandra5205
1

Product of coefficient of x^2 and constant term= 2*2= 4

2a^2 + 5a + 2=0

2a^2 + 4a + a +2 = 0

2a(a+2) +1(a+2) = 0

(2a+1) (a+2) = 0

a = -1/2 and -2

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