Question

please sove this problem
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Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

first find the area when the road roller completes 1 revolution:-

$1 \: revolution = csa \: of \: the \: cylinder$

h= 3.5 m

r= 1 m

$csa \: formula = \: 2\pi \: rh$

take pi =3.14 (given)

$csa = 2 \times 3.14 \times 1 \times 3.5$

$csa = 21.98 \: {m}^{2}$

↑ for 1 revolution.

$area \: covered \: in \: 200 \: revol = \: 200 \times csa$

$21.98 \times 200 = 4396 {m}^{2}$

the area covered by the road roller in 200 revolutions is 4,396 m²