Please take only LCM
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Step-by-step explanation:
Given tan(A+B)=3⟹A+B=60∘⋯(1)
tan(A−B)=31⟹A−B=30∘⋯(2)
(1)+(2)⟹2A=90∘⟹A=45∘
Put A value in (1)
⟹B=60∘−45∘=15∘
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