Math, asked by preetigmj, 1 month ago

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Answered by DaiwikPatel130806
0

Step-by-step explanation:

Given,

∠BOC = 90° and 2b−a = 65°

From the figure,

∠AOB +∠AOD +∠BOC +∠COD = 360°

= a + 2b + 90o + (2a+b+15) = 360°

= a + b = 85°

Add the given equation with this equation, we get

2b−a+a+b = 65° + 85°

b = 50°

then, a = 85° − b = 85° − 50° = 35°

∠AOB = a° = 35°, ∠AOD = 2b° = 2×50° = 100°

∠COD = (2a+b+15) = 2×35° + 50° + 15=135°

Answer =

∠AOB = 35°

∠AOD = 100°

∠COD = 135°

Hope this answer helps you.

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