Please tell answer.
Attachments:
Answers
Answered by
0
Step-by-step explanation:
Given,
∠BOC = 90° and 2b−a = 65°
From the figure,
∠AOB +∠AOD +∠BOC +∠COD = 360°
= a + 2b + 90o + (2a+b+15) = 360°
= a + b = 85°
Add the given equation with this equation, we get
2b−a+a+b = 65° + 85°
b = 50°
then, a = 85° − b = 85° − 50° = 35°
∠AOB = a° = 35°, ∠AOD = 2b° = 2×50° = 100°
∠COD = (2a+b+15) = 2×35° + 50° + 15=135°
Answer =
∠AOB = 35°
∠AOD = 100°
∠COD = 135°
Hope this answer helps you.
Please mark this answer as Brainliest if it helped you.
Similar questions