Question

please tell answer of Q no 2

Answer 1

${x}^{2} + px - r = 0 \\ \alpha \beta = - r \\ \alpha + \beta = - p ...(1)\\ \\ {x}^{2} + qx - r = 0 \\ \frac{ \alpha }{3} (3 \beta ) = - r \\ \frac{ \alpha }{3} + 3 \beta = - q....(2) \\ \\ \\ solve \: (1) \: and \: (2) \: find \: \alpha \: and \: \beta then \: multiply \: both \: to \: get \: r$