Math, asked by kamalkant0575, 9 months ago


please tell answer please ​

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Answers

Answered by SNethra2784
0

Answer:

Apm is 0585xhdey we ygg with afhir dihc ayhj

Answered by hiransnair03
0

Answer:

  • construction: draw a line from Mid of A to mid of CB and MP (where they intersect each other) lets take that point ad O

Step-by-step explanation:

consider TRIANGLE AMO and BOM

angle M = angle B (90 degree)

side AO = side AO (common)

by this triangles are equal

SO, AM =AB

AM= half AC

AB= half AP

so half AC = half AP

half cancled ( common in both )

so AC= AP

(hence it is proved that AB×AP=AC×AM)

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