Question

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Answer 1

Answer:

Step-by-step explanation:

Answer 2

Here is your answer mate:

11) (i) PS i m not having a figure. consider the 90° angle as B. foot of ladder as A and the window be C

Given: angle B = 90 degrees

          AB = 6m and BC = 8m

To find : Length of the ladder that is AC

In triangle ABC, by pythagoras theorem,

(AC)^2 = (AB)^2 + (BC)^2

(AC)^2 = (6)^2 + (8)^2

(AC)^2 = 36 + 64 = 100m

AC = 10m

thus, the length of the ladder is 10m

(ii) we know that the length of ladder is 10m and angle B is 90

According to the condition,

AB = 8m

to find : length BC (considering C as the end point of ladder and not the window)

in triangle ABC, by pythagoras theorem,

(AC)^2 = (AB)^2 + (BC)^2

(BC)^2 = (AC)^2 - (AB)^2

(BC)^2 = (10)^2 - (8)^2

(BC)^2 = 100 - 64 = 36

thus, BC = 6m

thus, the top of the ladder will reach upto 6m above the ground

12) Corresponding congruent parts

angle ABC = angle FED

angle BAC = angle EFD

angle BCA = angle EDF

AB = FE

BC = ED

AC = FD

hope this helps you buddy

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