English, asked by ektathaman216, 2 months ago

please tell correct answer​

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Answered by mrAdorableboy
28

a R b⇔a−b divisible by 3

Reflexive:

a R a⇔a−a divisible by 3 True

Therefore, the given relation R is a reflexive relation.

Symmetric:

a R b⇔a−b divisible by 3⇒ a−b=3k, where k is an integer.

Then,

b R a⇔b−a divisible by 3

Because b−a=−(a−b)=−3k which is divisible by 3.

Therefore, the given relation R is a symmetric relation.

Transitive:

a R b⇔a−b divisible by 3⇒ a−b=3k, where k is an integer.

b R c⇔b−c divisible by 3⇒ b−c=3p, where, p is an integer

Then,

a R c⇔a−c divisible by 3

Because a−c=(a−b)+(b−c)=3k+3p=3(k+p) which is divisible by 3.

Therefore, the given relation R is a transitive relation.

Since, the given relation R satisfies the reflexive, symmetric, and transitive relation properties, Therefore, it is an equivalence relation.

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