please tell factors of x^3-4x^2+4x
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well the question is unclear
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x³-4x²+4x = 0
x(x²-4x+4) = 0
x(x²-2x-2x+4) = 0
x(x(x-2)-2(x-2)) = 0
(x-0)(x-2)(x-2)=0
roots are 0,2,2
Step-by-step explanation:
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