Question

two pistons of hydraulic press have diameter 24 cm and 2cm. Calculate the force exerted by the longer piston when 40 kg wt is placed on smaller piston​

Answer 1

Answer:

56,448 N

Explanation:

Pascal's Law:

$\frac{f1}{a1} = \frac{f2}{a2}$

$\frac{40 \times 9.8}{\pi \times 0.01 \times 0.01} = \frac{f2}{\pi \times 0.12 \times 0.12}$