Question

please tell how to do ​

Answer 1

$\frac{ {7}^{3} }{ {7}^{x - 2} } = {7}^{7}$

$\frac{1}{ {7}^{x - 2} } = \frac{ {7}^{7} }{ {7}^{3} }$

$\frac{1}{ {7}^{x - 2} } = {7}^{4}$

${7}^{ - x + 2} = {7}^{4}$

$- x + 2 = 4$

$- x = 4 - 2$

$- x = 2$

$x = - 2$

${9}^{2x} \div {9}^{ - 5} = {9}^{13}$

${9}^{2x } = {9}^{13} \times {9}^{ - 5}$

${9}^{2x} = {9}^{13 + ( - 5)}$

${9}^{2x} = {9}^{8}$

$2x = 8$

$x = 4$

Answer 2

Step-by-step explanation:

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