please tell how to prove this
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Given: AB = AC
AE is median
which means, BE = CE.
Now , In ∆ ABC
AB = AC (Given)
AE = AE. (Common)
BE = CE. (Given)
therefore, ∆ ABE is congurent to ∆ ACE (By SSS)
AE is median
which means, BE = CE.
Now , In ∆ ABC
AB = AC (Given)
AE = AE. (Common)
BE = CE. (Given)
therefore, ∆ ABE is congurent to ∆ ACE (By SSS)
suyaib:
super
thx
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