Question

Please tell me ans friends

Answer 1

log27 to base 3 =3
so one root of the equation is 3
hence it shiuld satisfy the equation,so
3^2+3(5)+p=0
24+p=0
p=-24 so option c is correct

Answer 2

⛤HERE IS YOUR ANSWER⛤

$log_{3}(27) \\ = \frac{log27}{log3} \: \: \: (base \: of \: the \: log = e) \\ = \frac{log {3}^{3} }{log 3} \: \: (since \: {3}^{3} = 27) \\ = \frac{3log3}{log3} \: \: (since \: \: log {a}^{m} = mloga) \\ = 3$

So, x=3 is a root of the given quadratic equation and hence x=3 satisfies it. Thus
${x}^{2} + 5x + p = 0 \\ or \: \: {3}^{2} + 5.3 + p = 0 \\ or \: \: 9 + 15 + p = 0 \\ or \: \: p = - 24$

⛤HOPE THIS ⬆ HELPS YOU⛤