Math, asked by pooja455, 1 year ago

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Answered by OS13
2
Area of triangular park=(by heron's formula)
s =  \frac{a + b + c}{2}  =  \frac{120 + 80 + 50}{2}  = 125 \\ now \:  \sqrt{(s(s -a )(s - b)(s - c)) } \\  =   \:  \sqrt{(125 \times 5 \times 45 \times 75)} =
 \sqrt{5 \times 5 \times 5 \times 5  \times 3 \times 3 \times 5 \times 5 \times 5 \times 3}
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