Math, asked by gunas55198355, 4 months ago

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Answered by Flaunt
66

\huge\bold{\gray{\sf{Answer:}}}

\bold{Explanation:}

Question

The cost of fencing a circular race course at the rate of ₹ 8 per metre is ₹2112.Find the diameter of the race course.

Given:

Cost of fencing the circumference = Rs 2112

Cost of fencing one metre is Rs 8

To Find :

Diameter of the base course

If cost of fencing one metre is Rs 8

Then circumference of the Circle be \sf \dfrac{2112}{8}  = 264

 \sf=  > \pi \: d = 264

 \sf=  >  \dfrac{22}{7}  \times d = 264

 \sf=  > d = 264 \times  \dfrac{7}{22}

 \sf=  > 132 \times  \dfrac{7}{11}

\sf =  > 12 \times 7 = 84

\therefore Diameter of the race course is \bold{\red{ 84 \:m }}

Answered by Anonymous
0

\huge\bold{\gray{\sf{Answer:}}}

\bold{Explanation:}

Question

The cost of fencing a circular race course at the rate of ₹ 8 per metre is ₹2112.Find the diameter of the race course.

Given:

Cost of fencing the circumference = Rs 2112

Cost of fencing one metre is Rs 8

To Find :

Diameter of the base course

If cost of fencing one metre is Rs 8

Then circumference of the Circle be \sf \dfrac{2112}{8}  = 264

 \sf=  > \pi \: d = 264

 \sf=  >  \dfrac{22}{7}  \times d = 264

 \sf=  > d = 264 \times  \dfrac{7}{22}

 \sf=  > 132 \times  \dfrac{7}{11}

\sf =  > 12 \times 7 = 84

\therefore Diameter of the race course is \bold{\red{ 84 \:m }}

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