Question

please tell me answer

Answer 1

$x = \frac{ \sqrt{2a + b} + \sqrt{2a - b} }{ \sqrt{2a + b} - \sqrt{2a - b} }$
$= > \frac{x + 1}{x - 1} = \frac{ \sqrt{2a + b} }{ \sqrt{2a - b} }$
$= > \frac{(x + 1)^{2} }{ {(x - 1)}^{2} } = \frac{2a + b}{2a - b}$
$= > \frac{2( {x}^{2} + 1)}{4x} = \frac{2a}{b}$
$= > \frac{ {x}^{2} + 1 }{4x} = \frac{a}{b}$
$= > b {x}^{2} + b = 4ax$
$= > b {x}^{2} - 4ax + b = 0$


HOPE IT HELPS YOU.
IF YOU DO NOT UNDERSTAND ANYTHING TEXT ME.
PLEASE MARK THIS ANSWER BRAINLIEST...