Math, asked by raginiyadav99075, 1 month ago

please tell me answer​

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Answered by alvinam2010
3

1- 26 × (– 48) + (– 48) × (–36)

(– 48) [ 26 +(–36) ]

(– 48) × [-10]

= 480

2- Starting position of mine shaft is = 10m above ground

but,

it moves in opposite direction so it travels the distance (-350 m ) below the ground.

Total distance covered by mine shaft = 10m - (-350m)

= 10 + 350

= 360m

Now, taken to cover a distance of 6m by it = 1 minute

Time taken to cover a distance of 1m by it = \frac{1}{6\ }\min

6

1

min

Therefore, tie taken to a cover a distance of 360m = \frac{1}{6}\times\ 360\ =\ 60\ \min\ \

6

1

× 360 = 60 min

60 minutes = 1 hour

thus, in one hour the mine shraft reaches = 350 below the ground.

3. The sheet of paper is 12 1/2 cm long and 10 2/3 cm wide. Or

the length = 25/2 cm and the width = 32/3 cm.

The perimeter of the sheet of paper = 2[(25/2) + (32/3)]

= 2[75+64]/6

= 2*139/6

= 46.33 or 46 1/3 cm. Answer.

Its area = (25/2)(32/3) = 133.33 or 133 1/3 sq.cm. Answer.

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Hope it helps u lil cupcake.❣️

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