Physics, asked by asthakasyap94, 2 months ago

Differentiate log x with respect to x.     ​

Answers

Answered by llxdevilgirlxll
5

 \bold  \pink{Answer}

 \sf \: y \:  =  ({log \: x})^{x}

  \sf \: Taking \: log \: on \: both \:  sides \: , \: we \:get

 \sf \: log \: y \:  =  \: x \: log \: ( \: log \: x)

 \sf \: Differentiating \: w.r.t.x , \: we \: get,

 \sf \:  \frac{1 \: dy}{ \: y \: dx} =  \frac{x}{log \: x} \:   \times  \frac{1}{x} \:  +  \: log \: (log \: x)

 \sf \:  \frac{dy}{dx} \:  =    ({logx})^{x} ( \frac{1}{logx} + log(logx))

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