Math, asked by om9kcbse, 2 months ago

p+p²+p³+p⁴+p⁵+p⁶+p⁷)/(p‐³+p‐⁴+ p‐⁵+p‐⁶+p‐⁷+p‐⁸+p‐⁹)

Answers

Answered by anubhav3437

2

Answer:

p+÷£÷

Step-by-step explanation:

p+8@7÷~=¶×~{`=}ppHjwja

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