Question

Please tell me answer fast ​

Answer 1

Answer:

send the picture properly its not clear

Answer 2

Answer:

∠ACB = 70°

Step-by-step explanation:

$As, ADB \ is\ a\ triangle, \\\angle ABD + \angle DAB + \angle BDA = 180\textdegree \\ \to 50\textdegree+60\textdegree+\angle BDA = 180\textdegree \\ \to \angle BDA = 180\textdegree - (50\textdegree+60\textdegree)=180\textdegree - 110\textdegree = 70\textdegree\\\angle BDA \ and \ \angle ACB \ are \ inscribed \ angle \ on \ same \ arc\\So, \angle ACB = \angle BDA = 70\textdegree$