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Answer:
Given:
The length of a rectangle is 6 less than twice its breadth if the perimeter of the rectangle is 54.
To find:
Find its length & breadth.
Solution:
⚫Let breadth be x
⚫Let length of rectangle= 2x -6
⚫Perimeter of rectangle= 54.
Therefore,
We know that, perimeter of rectangle;
=) 2(length+breadth)
So,
=) 2(2x-6 + x) = 54
=) 2(3x -6) = 54
=) 6x -12 = 54
=) 6x = 54 +12
=) 6x = 66
=) x = 66/6
=) x = 11
Thus,
Breadth,x = 11
Length, 2x -6 = 2×11-6= 22 -6 = 16
Step-by-step explanation:
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