Chemistry, asked by manish200334, 8 months ago

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Answered by Itzraisingstar
4

Answer:

Explanation:

N = 8.0695*10^23 molecules. Therefore there is 8.0695*10^23 in 30L of methane(CH4). Originally Answered: How many molecules are in 30 liters of methane (CH4) at STP? We know that 1 mole of any substance contains exactly 22.7 liter of the volume at STP ( standard temperature and pressure) .

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