please tell me how to do this
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By converse of mid point theorem you prove midpoint in 1 triangle and again by converse of midpoint theorem you price the other triangle
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given
ABCD is a trapezium in which AB || DC, BD is diagonal and E is the mid point of AD And a line is drawn through E parallel to AB intersecting BC at F such that EF || AB
To prove
F is the mid point of BC
PROOF
Let EF intersect BD at P
In triangle ABD we have EP||AB(SINCE,EF||AB)
And E is the midpoint of AD(given)
by converse of mid point theorem P is the midpoint of BD.
similarly in triangle BCD We have PF||DC(SINCE, EF||AB& AB||DC)
P Is the mid point of BD(already proved)
by converse of mid point theorem F is the mid point of BC.
HENCE THE PROOF
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