Question

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Answer 1

Given : The Side of the Square = 21 cm

We know that : Area of Square is given by : Side × Side

⇒ The Area of the Given Square is 21 × 21 = 441 cm²

We can Notice that : The Given Square is divided into Four Triangles

As it is Square, The Four Triangles must be Congruent.

It means Area of Each Triangle will be One - Fourth of the Area of Square

⇒ Area of Each Triangle $\bf{= \frac{1}{4} \times Area\;of \;Square}$

⇒ Area of Two Shaded Triangles $\bf{= \frac{1}{2} \times Area\;of \;Square}$

⇒ Area of Two Shaded Triangles $\bf{= \frac{441}{2}\; cm^2}$

We know that : Two Semi-Circles of same Diameter form a Circle

In the Given Figure, The Semi-Circles are of Same Diameter, So they both form a Circle with Diameter equal to Side of the Square

We know that : Area of Circle is given by : πr²

⇒ Area of the Shaded portion of Circles $\bf{= \frac{22}{7} \times \frac{21}{2} \times \frac{21}{2}}$

⇒ Area of the Shaded portion of Circles $\bf{= \frac{693}{2}\; cm^2}$

Area of Shaded Region = Area of 2 Semi-Circles + Area of 2 Triangles

⇒ Area of Shaded Region $\bf{= (\frac{441}{2}) + (\frac{693}{2})}$

⇒ Area of Shaded Region $\bf{= (\frac{693 + 441}{2}) = (\frac{1134}{2}) = 567 \; cm^2}$

Answer 2

Answer:

567 cm²

Step-by-step explanation:

Given that ABCD is a square

Find area of ABCD:

Given that ABCD is a square

Area = Length x Length

Area = 21 x 21 = 441 cm²

Find the area of the two shaded triangles:

Area = 441 ÷ 2 = 220.5 cm²

Find the area of the 2 shaded semicircles:

Area = πr²

Area = π(21 ÷ 2)² = 346.5 cm²

Find the area of the shaded figure:

Area = 220.5 + 346.5 = 567 cm²

Answer: The area i s 567 cm²