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Hey Mate !!!!
From the given question,
GIVEN : We are given that ABCD is a parallelogram
i.e. AD = BC (∵ opposite sided of a parallelogram are equal)
i.e. AB = DC
And BD is the diagonal.
TO SHOW : ΔBAD≅ΔDCB
PROOF :
In ΔBAD and ΔDCB
AD = BC (∵ opposite sided of
AB = DC a parallelogram are equal)
BD = BD (common)
∴ By SSS congruence criteria,
ΔBAD≅ΔDCB
Hence Proved !!
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