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Answer will be 21 % Explanation is attached
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Answer:
Resistance of a wire
R = ρL/A
Find out how much the cross-sectional area changes.
Volume of a cylinder = cross-sectional area * h
V = Ah
Initial volume V₁ = A₁h₁
Final volume V₂ = A₂h₂
∴ Volume does not change .
Length of wire is increased by 10%.
A₁h₁ = A₂h₂
=> A₁/A₂ = h₂/h₁ = 1.1
So cross-sectional area will go down by 1.1
Now resistance calculation ,
Initial resistance R₁ = ρL₁/A₁
Final resistance R₂ = ρL₂/A₂
R₂/R₁ = (ρL₂/A₂) * (A₁/ρL₁)
R₂/R₁ = (L₂/L₁) * (A₁/A₂)
So the ratio is the product of the two
R₂/R₁ = 1.1 * 1.1
R₂/R₁ = 1.21
Therefore, resistance goes up by 21%.
Hope it helps!
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