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Answer:
Given:-
In the given figure XY parallel to QZ.
Also XY = QZ
To prove:-
ΔXMY congruent to ΔQMZ
proof:-
In tri xmy and qmz
XY= QZ ,GIVEN
ANGLE XMY = ANGLE QMZ, VERTICALLY OPPOSITE
ANGLE XYM= ANGLE QZM, SINCE XY PARALLEL TO QZ.
THUS TWO TRIANGLES ARE CONGRUENT BY ASA CRITERION
Hope this answer will help you
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