Math, asked by kailasauti4, 5 hours ago

Please tell me the answer and refer to the attachment above.

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Answers

Answered by rudrarawat13
1

Answer:

the answer for this is 639.2

Answered by Unni007
11

Let the given equation be x.

Given,

\sf{100 \times \dfrac{\sqrt{6^2+5^2}-\sqrt{5^2+4^2}}{\sqrt{5^2+4^2}}}

\sf{\implies x=100 \times \dfrac{\sqrt{6^2+5^2}-\sqrt{5^2+4^2}}{\sqrt{5^2+4^2}}}

As we know the values,

  • 6² = 36
  • 5² = 25
  • 4² = 16

Applying the values to the equation:

\sf{\implies x=100 \times \dfrac{\sqrt{36+25}-\sqrt{25+16}}{\sqrt{25+16}}}

\sf{\implies x=100 \times \dfrac{\sqrt{61}-\sqrt{41}}{\sqrt{41}}}

As we know the values,

  • √61 = 7.81
  • √41 = 6.40

\sf{\implies x=100 \times \dfrac{7.81-6.40}{6.40}}

\sf{\implies x=100 \times \dfrac{1.41}{6.40}}

\sf{\implies x=100 \times 0.2203125}

\sf{\implies x=22.03125}

\huge{\boxed{\bold{\sf{\therefore x=22.03125}}}}

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