Question

please tell me the answer!!
As fast as you can​

Answer 1

Answer:

This solution is of class 9 Rational numbers..

We will first rationalise and then put the final outcomes as " a=2, b route6=-5/6 route6 ".... so 2 and route 6 will be cancelled out and only b=-5/6 will be left..!

Hope it helped...Mark me Brainliest please..

Answer 2

Question :

Find the value of b in the following expression :

$\sf{ \dfrac{ \sqrt{2} + \sqrt{3} }{3 \sqrt{2} - 2\sqrt{3}} = 2 - b \sqrt{6} }$

Answer :

$\sf{ \dfrac{ \sqrt{2} + \sqrt{3} }{3 \sqrt{2} - 2 \sqrt{3} } \times \dfrac{ 3\sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } } = 2 - b \sqrt{6} \\ \\ \sf{ \dfrac{ \sqrt{2}(3 \sqrt{2} + 2 \sqrt{3} ) + \sqrt{3}(3\sqrt{2} + 2 \sqrt{3} ) }{ ({3 \sqrt{2} )}^{2} - ( {2 \sqrt{3} )}^{2} } } = 2 - b \sqrt{6} \\ \\ \sf{ \dfrac{6 + 2 \sqrt{6} + 3 \sqrt{6} + 6}{18 - 12} } = 2 - b \sqrt{6} \\ \\ \sf{ \dfrac{ 12 + 5 \sqrt{6} }{ 6} } = 2 - b \sqrt{6} \\ \\ \sf{ \cancel\frac{12}{6} \: {}^{ \: 2} + \frac{ 5\sqrt{6} }{6} } = 2 - b \sqrt{6} \\ \\ \sf{ 2 + \bigg( - \frac{5 }{6} \sqrt{6} \bigg) } = 2 - b \sqrt{6} \\ \\ {\boxed {\sf \red{b = - \frac{ 5}{6} }}}$