Question

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Answer 1

Step-by-step explanation:

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Solution. Clearly, the numbers between 250 and 1000 which are divisible by 3 are 252, 255, 258, …., 999. This is an A.P. with first term a = 252, common difference = 3 and last term = 999.

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Answer 2

10,a)The first number after 250 divisible by 3 is 252. and the number just before 1000 divisible by 3 is 999.

252 = 84 x 3 and 999 = 333 x 3

So there are 333–84+1 = 250 numbers between 250 and 1000 divisible by 3.

Their sum = (n/2)(a+l) = (250/2)(252+999) = 156375.