Question

please tell me the answer of ​

Answer 1

Step-by-step explanation:

6. p(x) = x^2-3x-m(m+3)

by adding and subtracting mx ,we get

p(x) = x^2-mx-3x+mx-m(m+3)

[x-(m+3) ] +m [x-(m+3)]

[x-(m+3)] (x+m)

p(x)=0 [x-(m+3)] (x+m)=0

[x-)m+3)] = or (x+m)=0

x=m+3 or x=-m

so, the zeroes of p(x) are -m and +3