Question

Please tell me the answer of these questions please​

Answer 1

Step-by-step explanation:

3) Solution

Let /\ ABC be an isosecles triangle

Base=BC=4/3 cm

Let AB=x

So BC =x

( two isosceles triangle are equal)

Given,

perimeter =4 7/15cm

= 4×15+2/15=60+2/15

=62/15

Also,

Perimeter = Sum of sides

= 62/15 = AB+AC+BC

62/15=x+x+4/3

62/15 =2x+4/3

2x+4/3=62/15

2x=62/15-4/3

2x=62-4×5/15

2x=62-20/15

2x=42/15

x= 42/15×1/2

x=21/15

x=7/5

x= 1 2/5

Length of remaining 2 sides =1 2/5