Question

please tell me this answers​

Answer 1

Let cost of chair be $x$ and let cost of table be $y$,

By the given information,

=> $6x+7y=2500$ ........ ( 1 )

=> $13x+11y=4610$ .....( 2 )

LCM of 6, 13 = 6 * 13 = 78

Multiplying ( 1 ) by 13 and ( 2 ) by 6,

=> $78x+91y=32500$ ....... ( 3 )

=> $78x+66y = 27660$ ....... ( 4 )

( 3 ) - ( 4 ),

=> $25y=4840$

=> $y = 193.6$

Substituting $y$ in ( 1 ) we get,

=> $x=1144.8$

Therefore,

C.P of a table = 193.6

C.P of a chair = 1144.8

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Answer 2

Question:

6 chairs and 7 tables can be bought for ₹ 2500 and 13 chairs and 11 tables can be bought for ₹ 4610. Find the cost price of a chair and a table.

Answer:

The price of a chair is ₹ 190.8 and price of a table is ₹ 193.6.

Step-by-step-explanation:

Let the cost price of a chair be ₹ x.

And the cost price of a table be ₹ y.

From the first condition,

6 chairs and 7 tables can be bought for ₹ 2500.

∴ 6x + 7y = 2500

⇒ 6x = 2500 - 7y

⇒ x = ( 2500 - 7y ) / 6 - - - ( 1 )

From the second condition,

13 chairs and 11 tables can be bought for ₹ 4610.

∴ 13x + 11y = 4610

⇒ [ 13 * ( 2500 - 7y ) / 6 ] + 11y = 4610

⇒ [ ( 32500 - 91y ) / 6 ] + 11y = 4610

⇒ ( 32500 - 91y + 66y ) / 6 = 4610

⇒ 32500 - 25y = 4610 * 6

⇒ 32500 - 25y = 27660

⇒ 32500 - 27660 = 25y

⇒ 25y = 4840

⇒ y = 4840 / 25

⇒ y = 968 / 5

⇒ y = ₹ 193.6

By substituting y = 193.6 in equation ( 1 ), we get,

x = ( 2500 - 7y ) / 6 - - - ( 1 )

⇒ x = ( 2500 - 7 * 193.6 ) / 6

⇒ x = ( 2500 - 1355.2 ) / 6

⇒ x = 1144.8 / 6

⇒ x = ₹ 190.8

∴ The price of a chair is ₹ 190.8 and price of a table is ₹ 193.6.