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Step-by-step explanation:
In triangle BEC and triangle BDC
BE=DC {sides of an isosceles triangle
equal}
BC=BC {common}
angle BEC=angleBDC {each 90°}
hence, triangle BEC is congruent to triangle BDC
{by SAS congruence}
hence, BD=CE {CPCT}
HENCED PROVED......!!
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