Question

please tell the and fast

Answer 1

Given,

(a/4 - b/2 + 1)²

We know that

(a+b+c)² = a² + b² + c² +2(ab+bc+ca)

Here a= a/4

b = (-b/2)

c= 1

So,

(a/4 - b/2 + 1)²

= (a/4)² +(-b/2)² + 1² +2( a/4* (-b/2) + (-b/2)*1 + 1*a/4)

= a²/16 + b²/2 + 1 + 2( -ab/8 - b/2 +a/4)

= a²/16 + b²/2 + 1 - ab/4 - b + a/2