Question

please tell the answer​

Answer 1

$\huge\orange{ \mid{ \underline{ \overline{ \tt ACB = 45°}} \mid}} \\ </p><p></p><p> </p><p> \huge\red{ \mid{ \underline{ \overline{ \tt ACB = 45° }} \mid}} \\ </p><p></p><p> \huge\red{ \mid{ \underline{ \overline{ \tt ABC = 45° }} \mid}}$

Step-by-step explanation:

Given in a rhombus ABCD ,angle DAC =45°.Find the measures of the following angles a) angles ACB b) ADB c) ABC

Now ABCD is a rhombus

Angle ADC = ABC (opposite angles are equal

Angle DAC = 45 degree

Let angle ADB = x

Now diagonals of rhombus bisect each other at right angles.

So angle AOD = 90 degree

Now AB is parallel to CD

So angle ACB = DAC = 45 degree (alternate interior angles)

So in triangle AOD we have,

So x + 45 + 90 = 180 (angle sum property of triangle)

Or x + 135 = 180

Or x = 180 – 135

Or x = 45 degree

So ADB = 45 degree, angle ACB = 45 degree and angle ABC = 45 degree