Question

What is the answer of (99)² but without directly multiplying ​

Answer 1

(99)²

(100 - 1)²

(100)² + 1² - 2*100*1

10000 + 1 - 200

9800 + 1

9801

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Answer 2

Step-by-step explanation:

$\boxed{\text{If a , b , c are in AP then show that the given term is also in AP }}$

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$\sf{a\bigg{(}\dfrac{1}{b} + \dfrac{1}{c} \bigg{)} \:,\: b\bigg{(} \dfrac{1}{c} + \dfrac{1}{a} \bigg{)} \:,\: c\bigg{(} \dfrac{1}{a} + \dfrac{1}{b} \bigg{)} }$