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Step-by-step explanation:
Since, PQRT is a parallelogram,
PQ║TR
So, ∠R+∠Q=180°
⇒2∠SRQ+2∠SQR=180°
⇒∠SRQ+∠SQR=90°---1
In ΔQSR,
∠S+∠SRQ+∠SQR=180°
From 1,
⇒∠S+90°=180°
⇒∠S=180°-90°=90°
Therefore, ∠S=90°
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