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Sum of 3 consecutive multiples of 7 is 777. Let the consecutive multiples of 7 be 7n, (7n + 7) and (7n + 14). ⇒ (7n) + (7n + 7) + (7n + 14) = 777 ⇒ 21n + 21 = 777 ⇒ 21n = 756 ⇒ n = 36 Therefore, multiples of 7 whose sum is 777 are (7 x 36), (7 x 36) + 7 and (7 x 36) + 14.That is 252, 259 and 266.
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