please tell the answer of27
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2.4 amp , I hope this will helpful
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ddasddas:
yes u are right
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Given, E=4.8V
R(s)=4+2 ohm=6ohm
so, R=1/(1/3+1/6)Ohm
=>R=1/(1/2)=2Ohm
Now, E=IR
=>I=E/R
=>I=4.8/2 Amperes
=>I=2.4 Amperes
Value of flowing current is 2.4A
R(s)=4+2 ohm=6ohm
so, R=1/(1/3+1/6)Ohm
=>R=1/(1/2)=2Ohm
Now, E=IR
=>I=E/R
=>I=4.8/2 Amperes
=>I=2.4 Amperes
Value of flowing current is 2.4A
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