Question

Please tell the right answer I'll mark.brainliest ​

Answer 1

Answer

$\rm Given,x=\dfrac{1}{3+2\sqrt{2}}\\\\\to \rm x=\dfrac{1}{3+2\sqrt{2}}\times \dfrac{3-2\sqrt{2}}{3-2\sqrt{2}}\\\\\to \rm x=\dfrac{3-\sqrt{2}}{(3)^2-(2\sqrt{2})^2}\ [\because\ (a+b)(a-b)=a^2-b^2]\\\\\to \rm x=\dfrac{3-2\sqrt{2}}{9-8}\\\\\to \rm x=\dfrac{3-2\sqrt{2}}{1}\\\\\to \bf x=3-2\sqrt{2}$

$\rm Now,\dfrac{1}{x}=\dfrac{1}{\frac{1}{3+2\sqrt{2}}}\\\\\to \bf \dfrac{1}{x}=3+2\sqrt{2}$

$\rm Now,solve, \\\\ \bf x-\dfrac{1}{x}\\\\:\implies \bf (3-2\sqrt{2})-(3+2\sqrt{2})\\\\:\implies \bf 3-2\sqrt{2}-3-2\sqrt{2}\\\\:\implies \bf -4\sqrt{2}$

So , Option (d) is correct

Answer 2

Answer:

-4√2

See image above...