Question

please tell the solution fast ​​

Answer 1

Answer 7 :

$6 - 6 {sin}^{2}θ \\ can \: be \: written \: as \: 6cos^{2} θ \\ 3 \cos((2θ) + 1) \\ ( - 6sinθ - 1)(sinθ + 1)$

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Answer 8 :

By Pythagoras Theorm,

$h²= b²+p²$

$x²= 13²-5²$

$x²= 169-25$

$x² = 144$

$x= 12$

Answer 2

Answer 7 :\begin{gathered}6 - 6 {sin}^{2}θ \\ can \: be \: written \: as \: 6cos^{2} θ \\ 3 \cos((2θ) + 1) \\ ( - 6sinθ - 1)(sinθ + 1)\end{gathered} 6−6sin 2 θcanbewrittenas6cos 2.

Answe 8 :

By Pythagoras Theorm,

h²= b²+p²

x²= 13²-5²

x²= 169-25

x² = 144

x= 12x