Math, asked by saadkamal3211, 11 months ago

Please tell this I have given you fifty points​

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Answered by shashankpaib
1

Answer:

1. a] 16^3^/^4 = [2^4^*^3^/^4] = 2^3 = 8

  b] 125^\frac{1}{3} = 5^3^*^\frac{1}{3} = 5^1=5

  c]5^\frac{3}{2} * 7^\frac{3}{2} = (5*7)^\frac{3}{2} = \sqrt{35^3} =35\sqrt{35}

2.a]4^\frac{3}{2} * 8^\frac{3}{2}=2^2^*^\frac{3}{2}* 2^3^*^\frac{3}{2} = 2^3*2^4^.^5= 2^7^.^5= 128\sqrt{2}

b]\frac{11^\frac{5}{2} }{11^\frac{3}{2} } = 11^\frac{5}{2}^-^\frac{3}{2}= 11^2=121

sorry for the delay

mark me as brainliest

and you said that you will give 50pts:)

Answered by navyasri231
0

Step-by-step explanation:

1.16^3/4=(2^4)3/4

=2^3

=8

2.125^-1/3=(5^3)-1/3

=5^-1

=1/5

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