Question

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Answer 1

Answer:

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Answer 2

Answer:

Parent element =.92U238, daughter element =.82Pb206. Let xα− and yβ- Particles be given out during the change .92U238→.82Pb206+x2He4+y.−1e0 Equating mass number on both sides

238=206+4xy×0

or x=8

Equating atomic number on both sides

92=82+2x+y(−1)

=82+2×8+y(−1)

or y=6

∴ Number of α-particles = 8, Number of `beta- particles = 6

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