Question

Please tell who are intelligent in math practical geometry

Answer 1

Answer:

Hello mate,

Step-by-step explanation:

Answer : Me All formulas as answer .

• Draw a triangle ( SSS Criterion )

Construct a triangle ABC , given that AB = 5 cm , BC = 6 cm and AC = 7cm .

* Step 1 : Draw a line segment BC of length 6 cm

* Step 2 : From B , point A is at a distance of 5 cm . So , with B as centre , draw an arc of radius 5 cm .

* Step 3 : From C , point A is at a distance of 7 cm So , with C as centre draw an arc of radius 7 cm .

* Step 4 : The point where both arcs meet is point A . Join A with point B and point C .

• Draw a triangle ( SAS Criterion )

Construct a triangle ABC , given that PQ = 3 cm , QR = 5.5 cm and angle PQR = 60 ° .

* Step 1 : Draw a line segment QR of length 5.5 cm

* Step 2 : At Q , draw QX making 60° with QR .

* Step 3 : With Q as centre , draw an arc of radius 3 cm . It cuts QX at at the point P .

* Step 4 : Join PR , Triangle PQR is now obtained .

• Draw a triangle ( ASA Criterion )

Construct triangle XYZ , given that XY = 6 cm , angle ZXY = 30° and angle XYZ = 100 ° .

* Step 1 : Draw XY of length 6 cm .

* Step 2 : At X , draw a ray of XP making it an angle of 30° .

* Step 3 : At Y , draw a ray of XQ making it an angle of 100° .

* Step 4 : The point of intersection of the two rays is point Z .

• Draw a triangle ( RHS Criterion )

Construct triangle LMN , right angled at M , given that LN = 5 cm and MN = 3 cm .

Step 1 : Draw MN of length 3 cm .

Step 2 : At M , draw MX perpendicular to MN .

Step 3 : With N as centre , draw an arc of radius 5 cm .

Step 4 : The point of intersection of the perpendicular and the arc is L . Join PN .