Question

Please tell with detailed solution


Detailed will be marked as brainliest

Answer 1

When he walks 30m north,

vector obtained is 30j^

Further When he walks 20m east, vector obtained is 20i^

Further he walks 30√2 south west,

which cannot be written either along x-axis or y-axis

so we take components of this movement along x-axis and y-axis

along x-axis = 30√2×cos45°

= 30i^ (towards west)

along Y-axis

= 30√2×sin45°=30j^ (towards south)

Now net movement, 30j^+20i^-30j^-30i^ = -10i^

This shows the displacement of 10m towards west from origin.

Hope this will be helpful for you,please mark me as brainliest.